Week Range
Jul 6, 2006
i have a time dimension table with week number,datesm month....
i want to add a column which will display the week range
something like this
Date DateRange
------------------------------------------------------
2005-01-02 00:00:00.000 2005-01-02 / 2005-01-08
2005-01-03 00:00:00.000 2005-01-02 / 2005-01-08
2005-01-04 00:00:00.000 2005-01-02 / 2005-01-08
2005-01-05 00:00:00.000 2005-01-02 / 2005-01-08
2005-01-06 00:00:00.000 2005-01-02 / 2005-01-08
2005-01-07 00:00:00.000 2005-01-02 / 2005-01-08
2005-01-08 00:00:00.000 2005-01-02 / 2005-01-08
View 3 Replies
ADVERTISEMENT
Feb 12, 2008
Hi,I'm
apologizing in advance for using someone else's brainpower on what is
basically a logic problem rather than a creative use of T-SQL, but it's
doing me head in.I have a table which contains information on
bookings for runs of advertising. This includes a BookingStart dateTime
field and a BookingEnd datetime field. Between BookingStart and
BookingEnd an ad is considered to be "live".What I need to do
is construct a query which, given a start date and and end date returns
a count of all the records which were "live" between those dates and -
here's the catch - each week must count separately. In other words if
my query asks for data across four weeks, and an ad was "live" for two
of those weeks, it should return a count of two.Any help much appreciated.Cheers,Matt
View 2 Replies
View Related
Nov 19, 2001
I need SQL to determine what the date range for the previous week was, ie
Start date 11/11/01 for Last Sunday through 11/17/01 the following Saturday.
The results will populate a drop down box for user queries.
Thanx.
View 1 Replies
View Related
Sep 17, 2007
How do i get only the records for everything with only the dates from last week (monday-friday)? I want to have this run every week for the previous week. Here's my stored procudure. Right now i have this to run for the day before, but now i need it for the week before. So its a range. Please Help. Thanks!
Code Snippet
CREATE PROCEDURE [dbo].[Testing_Out_Of_Stock_SKUS_WEEKLY]
(@Classification varchar(50))
AS
BEGIN
SELECT RC_STAT.dbo.Brand_Dimension.Report_Level,
RC_STAT.dbo.Brand_Dimension.[Cat vs Dog],
RC_STAT.dbo.Brand_Dimension.Item_Merged,
Qry_Sales_Group.Region_Key,
Qry_Sales_Group.Region,
Qry_Out_Of_Stock.product_structure_level,
Qry_Out_Of_Stock.product_entity_code,
Qry_Out_Of_Stock.cycle_day,
Qry_Out_Of_Stock.customer_code,
Qry_Out_Of_Stock.description,
Qry_Sales_Group.Code,
Qry_Sales_Group.SR_Name,
Qry_Sales_Group.Name AS Territory_Name,
Qry_Out_Of_Stock.Store_Name,
Qry_Out_Of_Stock.time_log,
Qry_Out_Of_Stock.out_of_stock,
Period_Code
FROM RC_STAT.dbo.Brand_Dimension INNER JOIN
dbo.Qry_Out_Of_Stock ON
RC_STAT.dbo.Brand_Dimension.Item_Key = dbo.Qry_Out_Of_Stock.product_entity_code COLLATE SQL_Latin1_General_CP1_CI_AS INNER JOIN
dbo.Qry_Sales_Group ON
dbo.Qry_Out_Of_Stock.sales_person_code = dbo.Qry_Sales_Group.SalesPerson_Purchaser_Code COLLATE Latin1_General_CI_AS
Where Classification=@Classification DateDiff(dd,0,dbo.Qry_Out_Of_Stock.time_log) =
case
when Datepart(Weekday, Getdate()) = 2 then datediff(dd,0,GetDate()) - 3
else datediff(dd,0,GetDate()) - 1
end
END
SET NOCOUNT OFF
View 5 Replies
View Related
Nov 3, 2006
Hi,
I don't know if this can be done, but hopefully one of the experts in this forum cna help me out.
I have a TimeOff table which contains 5 fields: timeoffID, employeename, startdate, enddate, and timofftype. I need to create a report which shows how many people take sick day (one of the timeofftypes) on each week day (i.e. Monday, Tuesday, Wednesday, and etc.) The problem is that I don't know how to convert the date range (from startdate to enddate) into indvidual week day for each timeoff record.
For example, on the table,
TimeoffID employeename startdate enddate timeofftype
1 Andy 11/02/2006 11/03/2006 Sick Day
2 Bill 11/03/2006 11/03/2006 Sick Day
The report needs to show:
Monday Tuesday Wednesday Thursday Friday Saturday Sunday
0 0 0 1 2 0 0
Thank you in advance!
View 4 Replies
View Related
Mar 31, 2008
Hello all,
I have the following SQL statement that works great for my purpose:
SELECT DATEADD(hh, DATEPART(hh, Date), DATEADD(d, DATEDIFF(d, 0, Date), 0)) AS TimePeriod, AVG(ZNT) AS Expr1, AVG(SAT) AS Expr2, AVG(RAT) AS Expr3,
AVG(RH) AS Expr4
FROM HVACValues
GROUP BY DATEADD(hh, DATEPART(hh, Date), DATEADD(d, DATEDIFF(d, 0, Date), 0))
ORDER BY TimePeriod
I'd like to do everything above but add to display only those records from 1/1/07 to 1/7/07...so a week's worth.
I'm no SQL expert but I assume that I'd add 'WHERE TimePeriod = ....' Any help is much appreciated!
Thank you very much.
View 3 Replies
View Related
Apr 22, 2015
I require some scripting to return data which sits in a rolling weeks date range of the current week.
For example, on a Monday I want to return data from the previous day (Sunday to the previous Monday).
On a Tuesday I want to return data from the previous day (Monday to the up coming Sunday).
On a Wednesday I want to return data from the Monday (previous 2 days ago to the upcoming Sunday)
On a Thursday I want to return data from the Monday (previous 3 days ago to the upcoming Sunday)
And so forth.
So I have my SQL script which works with static, fixed date ranges. But I need this additional dynamic date range logic built in.
View 1 Replies
View Related
Nov 30, 2015
We are trying to compare our current calendar week (based on Monday being the first day of the week) with the previous calendar week.
I'm trying to produce a line chart with 2 axis:
- x axis; the day of the week (Mon, Tues, Wed etc - it is fine for this to be a # rather than text e.g. 1 = Mon, 2 = Tues etc)
- y axis; the cumulative number of orders
The chart needs two series:
Previous Week. The running count of orders placed that week.
Current Week. The running count of orders placed this week.
Obviously in such a chart the 'Current Week' series is going not going to have values along the whole axis until the end of the week. This is expected and the aim of the chart is to see the current week compares against the previous week for the same day.
I have two tables:
Orders TableCalendar Table
The calendar table's main date column is [calDate] and there are columns for the usual [calWeekNum], [calMonth] etc.
My measure for counting orders is simply; # Orders: = countrows[orders].
How do I take this measure and then work out my two series. I have tried numerous things such as adapting TOTALMTD(), following articles such as these:
- [URL] ...
- [URL] ...
But I have had no luck. The standard cumulative formulas do work e.g. if I wanted a MTD or YTD table I would be ok, it's just adjusting to a WTD that is causing me big issues.
View 3 Replies
View Related
Apr 9, 2013
How can I get Saturday's date given the week number?
This is my week number, SELECT DATEPART(WEEK, DATEADD(MONTH, +3, ApptDt2)). I need to get Saturday's date from this week.
View 9 Replies
View Related
Sep 17, 2015
i have the following table I need to select dates grouping them by weeks, my week start is Saturday to Friday
CREATE TABLE weekdays
(
datevalue datetime NOT NULL
, numericvalue INT NOT NULL
);
INSERT INTO weekdays (datevalue, numericvalue) VALUES
[code]....
The output should look like this
weeknototalvalue
362015-09-01 00:00:00.000
362015-09-02 00:00:00.000
372015-09-07 00:00:00.000
372015-09-08 00:00:00.000
382015-09-12 00:00:00.000
382015-09-13 00:00:00.000
382015-09-14 00:00:00.000
392015-09-19 00:00:00.000
View 4 Replies
View Related
May 23, 2007
Hi all,
I'd like to add a yesterday dimension member to a new dimension, like a "Time Utility" dimension, that references the second last day of non empty data in a cube.
At the moment, I'm doing this:
Code Snippet
create member [MIA DW].[DATE TIME].[Date].[Yesterday]
as [DATE TIME].[Date].&[2007-01-01T00:00:00]
select [Measures].members on 0,
non empty [DATE TIME].[Date].members on 1
from [MIA DW]
But the [yesterday] member does not seem to belong to [DATE TIME].[Date].members?
So I guess there's two questions:
1) Can I have a new empty dimension which contains all these special members like "Yesterday" or "This Week" and "Last Week" (these last two obviously refer to a set of Dates)
2)How come the Yesterday member is not returned by the .members function?
Thanks
Greg
View 3 Replies
View Related
Jan 29, 2014
I am adding week hrs using while loop , but it can continue next week hrs also.
I can get every week start hrs while update @tem1 table
employeeidreportdatereportatleftattoaccountwrhrn
12902014-01-29 00:00:00.00009:3019:1556001
12902014-01-28 00:00:00.00009:0018:4555802
12902014-01-27 00:00:00.00009:0018:455585583
12902014-01-25 00:00:00.00008:0010:0012004 -- week end
12902014-01-24 00:00:00.00009:1718:4554105
12902014-01-23 00:00:00.00009:1918:4654606
12902014-01-22 00:00:00.00009:1718:4754507
12902014-01-21 00:00:00.00009:1618:3552608
12902014-01-20 00:00:00.00009:1818:555435439
My loop statement
while(select MAX(wrh) from @tem1 where wrh = 0) < 1
begin
update @tem1
set wrh = (select toaccount from @tem1
where reportdate = (select min(reportdate) from @tem1 where wrh = 0))+(select max(wrh) from @tem1)
where wrh = (select max(wrh) from @tem1 where wrh = 0 )
and reportdate = (select min(reportdate) from @tem1 where wrh = 0)
end
this is the result while executing loop statement .
employeeidreportdatereportatleftatdehdrhwehwrh
129029 Jan 201409:3019:15008:0009:20024:00065:54
129028 Jan 201409:0018:45008:0009:18016:00056:34
129027 Jan 201409:0018:45008:0009:18008:0009:18
129025 Jan 201408:0010:00005:0002:00045:00047:16 -- week end
129024 Jan 201409:1718:45008:0009:01040:00045:16
129023 Jan 201409:1918:46008:0009:06032:00036:15
129022 Jan 201409:1718:47008:0009:05024:00027:09
129021 Jan 201409:1618:35008:0008:46016:00018:04
129020 Jan 201409:1818:55008:0009:03008:0009:03
How to update only that week hrs , don't continue next week...
View 4 Replies
View Related
Apr 29, 2008
In my reports I am extracting the data of number of people joined in all the weeks of the year. And in one of reports I have to extract the data of the number of people joined until the last week from the first week. I am trying out all the logics but nothing is working for me as such. Can any one help me with this issue??????
View 4 Replies
View Related
Jul 23, 2015
I need a Select sentence that return me the first week of the month for a given week.
For example If I have week number 12 (Begins 2015/03/16 and Ends 2015/03/22) I need that returns 9, I mean Week number 9 wich is the first week of march (having in mind @@DATEFIRST).
I only need give a week number of the year and then returns the week number of the first week of that month.
View 34 Replies
View Related
Feb 2, 2008
I'm looking for a way to convert the [week number, year] back to the date for the 1st day of that week.
Example (assuming DATEFIRST has been set to 1) : Week 3, 2008 = January 14, 2008
Is there a SQL function that will do this?
Thanks,
Mike
View 11 Replies
View Related
Jun 6, 2006
seriously now
View 1 Replies
View Related
Aug 15, 2006
I have a query that run every day to update a summary table which has week number and day of week. what I currently do is delete all records from the summary table and then summarize all the data availabe from four tables adn then populate the table daily. I want to know if I can run the update query to run only for the week number and day of week depending on getdate. Can I do this?
Please help..
View 1 Replies
View Related
Jan 18, 2006
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK returns the ISO 8601 Year Week Day of Week in format YYYY-W01-D for the date passed. W01 represents the week of the year from W01 through W53, and D represents the day of the week with 1 = Monday through 7 = Sunday.
The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.
This code creates the function and demos it for the first day, first date+60, and first date+364 for each ISO week/year from 1990 to 2030.
drop function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
GO
create function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
(
@Datedatetime
)
returnsvarchar(10)
as
/*
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK
returns the ISO 8601 Year Week Day of Week
in format YYYY-W01-D for the date passed.
*/
begin
declare @YearWeekDayOfWeekvarchar(10)
Select
--Format to form YYYY-W01-D
@YearWeekDayOfWeek =
convert(varchar(4),year(dateadd(dd,7,a.YearStart)))+'-W'+
right('00'+convert(varchar(2),(datediff(dd,a.YearStart,@Date)/7)+1),2) +
'-'+convert(varchar(1),(datediff(dd,a.YearStart,@Date)%7)+1)
from
(
select
YearStart =
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aaa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aaa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aaa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aaa
) aa
) a
return @YearWeekDayOfWeek
end
go
-- Execute function on first day, first day+60,
-- and first day+364 for years from 1990 to 2030.
select
DT= convert(varchar(10),DT,121),
YR_START_DT =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT),
YR_START_DT_60 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+60),
YR_START_DT_365 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+364)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a
Function Test Results:
DT YR_START_DT YR_START_DT_60 YR_START_DT_364
---------- ----------- -------------- ---------------
2006-01-18 2006-W03-3 2006-W11-7 2007-W03-3
1990-01-01 1990-W01-1 1990-W09-5 1991-W01-1
1990-12-31 1991-W01-1 1991-W09-5 1992-W01-1
1991-12-30 1992-W01-1 1992-W09-5 1992-W53-1
1993-01-04 1993-W01-1 1993-W09-5 1994-W01-1
1994-01-03 1994-W01-1 1994-W09-5 1995-W01-1
1995-01-02 1995-W01-1 1995-W09-5 1996-W01-1
1996-01-01 1996-W01-1 1996-W09-5 1997-W01-1
1996-12-30 1997-W01-1 1997-W09-5 1998-W01-1
1997-12-29 1998-W01-1 1998-W09-5 1998-W53-1
1999-01-04 1999-W01-1 1999-W09-5 2000-W01-1
2000-01-03 2000-W01-1 2000-W09-5 2001-W01-1
2001-01-01 2001-W01-1 2001-W09-5 2002-W01-1
2001-12-31 2002-W01-1 2002-W09-5 2003-W01-1
2002-12-30 2003-W01-1 2003-W09-5 2004-W01-1
2003-12-29 2004-W01-1 2004-W09-5 2004-W53-1
2005-01-03 2005-W01-1 2005-W09-5 2006-W01-1
2006-01-02 2006-W01-1 2006-W09-5 2007-W01-1
2007-01-01 2007-W01-1 2007-W09-5 2008-W01-1
2007-12-31 2008-W01-1 2008-W09-5 2009-W01-1
2008-12-29 2009-W01-1 2009-W09-5 2009-W53-1
2010-01-04 2010-W01-1 2010-W09-5 2011-W01-1
2011-01-03 2011-W01-1 2011-W09-5 2012-W01-1
2012-01-02 2012-W01-1 2012-W09-5 2013-W01-1
2012-12-31 2013-W01-1 2013-W09-5 2014-W01-1
2013-12-30 2014-W01-1 2014-W09-5 2015-W01-1
2014-12-29 2015-W01-1 2015-W09-5 2015-W53-1
2016-01-04 2016-W01-1 2016-W09-5 2017-W01-1
2017-01-02 2017-W01-1 2017-W09-5 2018-W01-1
2018-01-01 2018-W01-1 2018-W09-5 2019-W01-1
2018-12-31 2019-W01-1 2019-W09-5 2020-W01-1
2019-12-30 2020-W01-1 2020-W09-5 2020-W53-1
2021-01-04 2021-W01-1 2021-W09-5 2022-W01-1
2022-01-03 2022-W01-1 2022-W09-5 2023-W01-1
2023-01-02 2023-W01-1 2023-W09-5 2024-W01-1
2024-01-01 2024-W01-1 2024-W09-5 2025-W01-1
2024-12-30 2025-W01-1 2025-W09-5 2026-W01-1
2025-12-29 2026-W01-1 2026-W09-5 2026-W53-1
2027-01-04 2027-W01-1 2027-W09-5 2028-W01-1
2028-01-03 2028-W01-1 2028-W09-5 2029-W01-1
2029-01-01 2029-W01-1 2029-W09-5 2030-W01-1
2029-12-31 2030-W01-1 2030-W09-5 2031-W01-1
2030-12-30 2031-W01-1 2031-W09-5 2032-W01-1
(43 row(s) affected)
CODO ERGO SUM
View 2 Replies
View Related
May 2, 2007
hi friends,
how to get the date of the first/last day of the week in sql...
can any one help me
Cheers,
raj
View 5 Replies
View Related
Aug 16, 2006
I am attempting to write a SQL query that retrieves info processed between two times (ie. 2:00 pm to 6:00 pm) during a date range (ie. 8/1/06 to 8/14/06)... I am new to SQL and am perplexed... I have referenced several texts, but have not found a solution. Even being pointed in the right direction would be greatly appreciated!!
View 6 Replies
View Related
Nov 26, 2014
I'm running a pre-defined script which used to work fine on a file which was resupplied every month. below is the script used and the error message. looking at the error I assume that there is a rouge record within the file but have looked in Textpad and cannot find it.
UPDATE [matching].[dbo].[hot_nov] SET [AOV] = (CAST([Demand] AS DECIMAL)/CAST([Orders] AS INT)) WHERE [Demand] <> '';
UPDATE [matching].[dbo].[hot_nov] SET [POST2] = left([PostCode], PATINDEX('%[0-9]%', [PostCode] + '1') - 1) ;
UPDATE [matching].[dbo].[hot_nov] SET [POST4] = left([PostCode],LEN([PostCode])-4);
UPDATE [matching].[dbo].[hot_nov] SET [POST6] = left([PostCode],LEN([PostCode])-2);
error message
(1000 row(s) affected)
Msg 245, Level 16, State 1, Line 181
Conversion failed when converting the varchar value '2014-09-03 00:00:00' to data type int.
View 5 Replies
View Related
Apr 6, 2015
I have 2 tables, one is table A which stores Resources Assign to work for a certain period. The structure is as below
Name StartDate EndDate
Tan 2015-04-01 08:30:00.000 2015-04-01 16:30:00.000
Max 2015-04-01 08:30:00.000 2015-04-01 16:30:00.000
Alan 2015-04-01 16:30:00.000 2015-04-02 00:30:00.000
The table B stores the item process time. The structure is as below
Item ProcessStartDate ProcessEndDate
V 2015-04-01 09:30:10.000 2015-04-01 09:34:45.000
Q 2015-04-01 10:39:01.000 2015-04-01 10:41:11.000
W 2015-04-01 11:44:00.000 2015-04-01 11:46:25.000
A 2015-04-01 16:40:10.000 2015-04-01 16:42:45.000
B 2015-04-01 16:43:01.000 2015-04-01 16:45:11.000
C 2015-04-01 16:47:00.000 2015-04-01 16:49:25.000
I need to select the item which process in 2015-04-01 16:40:00 and 2015-04-01 17:30:00. Beside that I need to know how many resource is assigned to process the item in that period of time. I only has the start date is 2015-04-01 16:40:00 and end date is 2015-04-01 17:30:00. How I can select the data from both tables. There is no need for JOIN, just seperate selections.
Another item process time is in 2015-04-01 10:00:00 and 2015-04-04 11:50:59.
The result expected is
Table A
Name StartDate EndDate
Alan 2015-04-01 16:30:00.000 2015-04-02 00:30:00.000
Table B
Item ProcessStartDate ProcessEndDate
A 2015-04-01 16:30:10.000 2015-04-01 16:32:45.000
B 2015-04-01 16:33:01.000 2015-04-01 16:35:11.000
C 2015-04-01 16:37:00.000 2015-04-02 16:39:25.000
Scenario 2 expected result
Table A
Name StartDate EndDate
Tan 2015-04-01 08:30:00.000 2015-04-01 16:30:00.000
Max 2015-04-01 08:30:00.000 2015-04-01 16:30:00.000
Table B
Item ProcessStartDate ProcessEndDate
Q 2015-04-01 10:39:01.000 2015-04-01 10:41:11.000
W 2015-04-01 11:44:00.000 2015-04-01 11:46:25.000
View 8 Replies
View Related
Jul 29, 2013
I have a need to select rows where values in a column are within a range AND ALSO the first row that is highest (MAX) but just UNDER the range. For example:
NAME VAL
Jim 4
John 5
Tom 6
Julie 7
Rich 8
Rob 9
RANGE TO SELECT is 6-8 (inclusive)
Rows with a value in the range are returned (6, 7, & 8) as well as the row with a highest value that is JUST BELOW the range (5)
NAME VAL
John 5
Tom 6
Julie 7
Rich 8
View 2 Replies
View Related
May 18, 2007
How to find the saturday in the current week using sql server 2000
View 5 Replies
View Related
Jun 7, 2001
I am trying to convert a field that has a Date and Time in smallDateTime format into something that will give me the day of the week that each Date corresponds to. For example, if my Date/Time field says "Jun 7 2001 09:30:00" I want my Day field to automatically say "Thursday". Is there a function that will do this? Or is there something close that will convert a variable of smalldatetime format into a number 0-6 which then can be converted to a day of the week?
View 3 Replies
View Related
Feb 16, 2000
Is it possible to write a sql querry to display day of the week?
If it is what is the syntax Pls.
Elsie Reed
View 2 Replies
View Related
May 11, 2008
Is there a way I can filter dates for last week (May 4 - 10)? This mean that every Mondays, I'll be getting last week's date range. Thanks
View 17 Replies
View Related
Dec 11, 2001
How do I see which is the first day of the week setting in my server?
I was reading about @@DATEFIRST and SET FIRSTDATE, etc. But I don't want to set anything, I just want to know what is the first day of the week set on my server.
Any help will be appreciated.
Thanks
OPi
View 2 Replies
View Related
Apr 27, 2005
I need to write a user defined function that will return the date of the first day of a week when provided with the week number. I had an idea of using a while loop with that will keep adding 1 day from January 1st until the week number (found via the DATEPART function) is equal to the supplied week number. Not sure if this is the best way though - any ideas?
Donald.
View 2 Replies
View Related
Jan 24, 2006
Is there anyway to get SQL to convert a date to days of the week?
Example, I have a query where the date is "01/01/2006" but I would like it to display "Sunday". Thank you.
View 2 Replies
View Related
Feb 19, 1999
this might not be considered a sql problem but here goes anyways.
it was 53 weeks in 1998. however it seems like my computer considered week 53 last year as week 1 in 1999.
so when i perform an operation like this:
select datepart(wk, getdate())
next weeks number is returned. what to do?
View 1 Replies
View Related
Jun 21, 2004
Hi,
Is there an easy way to get the position (or number) of the week from a date? By position, I mean week number 1 if we are january 1st. For example:
Date | Week postion
=====================
2001-01-05 | 1
1996-12-28 | 52
1987-06-15 | 26
Thanks a lot,
Skip.
View 1 Replies
View Related
Jan 16, 2006
How would you write a query to create a report based on weeks ?
i want to use the reporting services dropdown parameter
to query between weeks as in 01/09/06 to 01/13/06 ?
View 1 Replies
View Related
